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Question

Solve the following problem:
Maximize Z=Px1+4x2
Subject to: 3x1+x26
x1+2x24
x23
No lower bound constraint for x1

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Solution

The third constraint can be re-written as x23. The solution space satisfying constraints is shown shaded in the figure.
A(3,3) and B(10,3) value of the objective functions Z=x1+4x2 at these vertices are
Z(A)=312=9, Z(B)=1012=22
Thus the maximum value of Z occurs at A. Hence the solution to the problem is
x1=2,x23;Zmax=9

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