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Question

Solve the following problems and verify the data in each case by drawing Venn diagrams. In a class, 50 students offered Mathematics, 42 offered Biology and 24 offered both the subjects. Find the number of students, who offer Mathematics only.

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Solution

Let the total number of students who offered mathematics be n(M) and number of students who offered biology be n(B).

Then, the number of students who offered both mathematics and biology is n(MB) and the number of students who offered mathematics only is n(M)n(MB)

We know that n(AB)=n(A)+n(B)n(AB) where A and B are the respective sets.

Here, it is given that in a class, 50 students offered mathematics, 42 offered biology and 24 offered both the subjects, that is n(M)=50,n(B)=42 and n(MB)=24 and therefore,

n(M)n(MB)=5024=26

Hence, the number of students who offered mathematics only is 26.

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