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Question

Solve the following quadratic equation.
37x2+4x+7=0

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Solution

37x2+4x7=0

37x2+4x7=0

37x23x+7x7=0

3x(7x1)+7(x1)=0

(3x+7)(7x1)=0

either (3x+7)=0 or (7x1)=0

x=7/3 or 1/7

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