CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Solving a Quadratic Equation by Completion of Squares Method

Solve the fol...

Question

Solve the following quadratic equation.
$4 x^{2} + 4 b x - (a^{2} - b^{2}) = 0$

Open in App

Solution

Consider the given equation.
$4 x^{2} + 4 b x - (a^{2} - b^{2}) = 0$
$4 x^{2} + 4 b x + b^{2} - a^{2} = 0$
$(2 x + b)^{2} - a^{2} = 0$
$(2 x + b - a) (2 x + b + a) = 0$
$2 x + b - a = 0$ Or $2 x + b + a = 0$
$x = \frac{a - b}{2}$ Or $x = - \frac{a + b}{2}$

Suggest Corrections

thumbs-up

2

Similar questions

Q. Solve the following quadratic equations by factorization:

4 x^{2} + 4 b x - (a^{2} - b^{2}) = 0

Q. Solve the following quadratic equation by completing the square:

4 x^{2} + 4 b x - (a^{2} - b^{2}) = 0

Q. Solve each of the following quadratic equations:

4 x^{2} + 4 b x - (a^{2} - b^{2}) = 0

Q. Solve the following equation by using the method of completing the square:

4 x^{2} + 4 b x - (a^{2} - b^{2}) = 0

Q. Solve each of the following equation by using the method of completing the square:

4 x^{2} + 4 b x - (a^{2} - b^{2}) = 0

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Solving QE by Completing the Square

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Solving a Quadratic Equation by Completion of Squares Method

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon