Question

Solve the following quadratic equation by completing square method.
$x^2-4x-3=0$.

Answer 1

$x^2-4x-3=0$

$\Rightarrow x^2-4x+4-7=0$

$\Rightarrow (x-2{)}^2-7=0$

$\Rightarrow (x-2{)}^2=7$

$\therefore x-2=-\sqrt{7},+\sqrt{7}$
$x=2-\sqrt{7},2+\sqrt{7}$