CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Zeroes of a Polynomial

Solve the fol...

Question

Solve the following quadratic equation by factorisation.
$2 x^{2} - 2 x + \frac{1}{2} = 0$ .

Open in App

Solution

$2 x^{2} - 2 x + \frac{1}{2} = 0 4 x^{2} - 4 x + 1 = 0 4 x^{2} - 2 x - 2 x + 1 = 0 2 x (2 x - 1) - 1 (2 x - 1) = 0 (2 x - 1) (2 x - 1) = 0$

Suggest Corrections

thumbs-up

2

Similar questions

Q. Solve the following quadratic equations by factorisation.
(1) x² – 15x + 54 = 0
(2) x² + x – 20 = 0
(3) 2y² + 27y + 13 = 0
(4) 5m² = 22m + 15
(5) 2x² – 2x +

\frac{1}{2}

6 x - \frac{2}{x} = 1

\sqrt{2} x^{2} + 7 x + 5 \sqrt{2} = 0

to solve this quadratic equation by factorisation, complete the following activity.
(8)

3 x^{2} - 2 \sqrt{6} x + 2 = 0

2 m (m - 24) = 50

25 m^{2} = 9

7 m^{2} = 21 m

m^{2} - 11 = 0

Q. Solve the given quadratic equation by factorisation method,

(2 x - 3) = \sqrt{2 x^{2} - 2 x + 21}

Q. Solve the given quadratic equation by factorisation method,

\sqrt{2} x^{2} + 7 x + 5 \sqrt{2} = 0

Q. Solve the following quadratic equations by factorisation:

x^{2} - (\sqrt{2} + 1) x + \sqrt{2} = 0

Q. Solve the following quadratic equation by factorisation.

x^{2} - 7 x - 18 = 0

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Zeroes of a Polynomial concept

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Zeroes of a Polynomial

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon