wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following quadratic equation by factorisation method: x22ax+a2b2=0

Open in App
Solution

x22ax+(a2b2)=0(x22ax+a2)b2=0
(xa)2b2=0 (by applying a22ab+b2=(ab)2 formula)
this is of the form a2b2=(ab)(a+b)
Hence (xa)2b2=0 becomes
(xab)(xa+b)=0xab=0,xa+b=0x=a+b,x=ab
Hence these are the required roots of the given equation.

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Zeroes of a Polynomial concept
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon