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Byju's Answer
Standard IX
Mathematics
Zeroes of a Polynomial
Solve the fol...
Question
Solve the following quadratic equation by factorisation method:
x
2
−
2
a
x
+
a
2
−
b
2
=
0
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Solution
x
2
−
2
a
x
+
(
a
2
−
b
2
)
=
0
⟹
(
x
2
−
2
a
x
+
a
2
)
−
b
2
=
0
⟹
(
x
−
a
)
2
−
b
2
=
0
(by applying
a
2
−
2
a
b
+
b
2
=
(
a
−
b
)
2
formula)
this is of the form
a
2
−
b
2
=
(
a
−
b
)
(
a
+
b
)
Hence
(
x
−
a
)
2
−
b
2
=
0
becomes
(
x
−
a
−
b
)
(
x
−
a
+
b
)
=
0
⟹
x
−
a
−
b
=
0
,
x
−
a
+
b
=
0
⟹
x
=
a
+
b
,
x
=
a
−
b
Hence these are the required roots of the given equation.
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