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Question

Solve the following quadratic equation by factorisation method: x22ax+a2b2=0

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Solution

x22ax+(a2b2)=0(x22ax+a2)b2=0
(xa)2b2=0 (by applying a22ab+b2=(ab)2 formula)
this is of the form a2b2=(ab)(a+b)
Hence (xa)2b2=0 becomes
(xab)(xa+b)=0xab=0,xa+b=0x=a+b,x=ab
Hence these are the required roots of the given equation.

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