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Question

Solve the following quadratic equation by factorization :
2x+1+32(x2)=235x;x0,1,2

The roots is 4

A
True
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B
False
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Solution

The correct option is A True
2x+1+32(x2)=235x

4(x2)+3(x+1)2(x+1)(x2)=235x

=4x8+3x+32(x22x+x2)=235x

7x52(x2x2)=235x

7x52x22x4=235x

35x225x=46x246x92
11x244x+23x92=0
11x(x4)+23(x4)=0
(x4)(11x+23)=0
x4=0 and 11x+23=0
x=4 and x=2311


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