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Question

Solve the following quadratic equation by factorization.
3x+112=23x1,x1,13

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Solution

3x+112=23x1,x1,13

6x12x+2=23x1

5x2x+2=23x1

(5x)(3x1)=2(2x+2)

15x53x2+x=4x+4

16x53x24x4=0

3x2+12x9=0

3x212x+9=0

x24x+3=0

x2x3x+3=0

x(x1)3(x3)=0

(x3)(x1)=0

Therefore,

x=3,1


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