Solve the following quadratic equation by factorization :
(i) $(2 x + 3) (3 x - 7) = 0$
(ii) $(x - 2)^{2} - 25 = 0$

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Solution

(i) $(2 x + 3) (3 x - 7) = 0$

$2 x + 3 = 0, 3 x - 7 = 0$

$x = \frac{- 3}{2}, \frac{7}{3}$

(ii) $(x - 2)^{2} - 25 = 0$

$(x - 2)^{2} = 25$

$(x - 2) = 5, - 5$

$x - 2 = 5, x - 2 = - 5$

$x = 7, x = - 3$

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