Solve the following quadratic equation by factorization method: $3 x^{2} - 5 x - 12 = 0$

{- \frac{4}{3}, 3}

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{\frac{4}{3}, 3}

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{- \frac{4}{3}, - 3}

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None of these

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Solution

The correct option is A ${- \frac{4}{3}, 3}$
Given equation is $3 x^{2} - 5 x - 12 = 0$

$\Rightarrow$ $3 x^{2} - 9 x + 4 x - 12 = 0$

$\Rightarrow$ $3 x (x - 3) + 4 (x - 3) = 0$

$\Rightarrow$ $(x - 3) (3 x + 4) = 0$

$\Rightarrow$ $x - 3 = 0$ and $3 x + 4 = 0$

$\Rightarrow$ $x = 3$ and $x = - \frac{4}{3}$

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