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Methods of Solving a Quadratic Equation

Solve the fol...

Question

Solve the following quadratic equation by factorization method:
(ii) $x^{2} + (1 - 2 i) x - 2 i = 0$

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Solution

We have, $x^{2} + (1 - 2 i) x - 2 i = 0$
$\Rightarrow x^{2} + x - 2 i x - 2 i = 0$

$\Rightarrow x (x + 1) - 2 i (x + 1) = 0$

$\Rightarrow (x + 1) (x - 2 i) = 0$

$\Rightarrow (x + 1) = 0 o r (x - 2 i) = 0$

$\Rightarrow x = - 1 o r x = 2 i$

Hence, the roots are $- 1 a n d 2 i$

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Similar questions

Solve the following quadratic equations by factorization method :

(i) $x^{2} + 10 i x - 21 = 0$

(ii) $x^{2} + (1 - 2 i) x - 2 i = 0$

(iii) $x^{2} - (2 \sqrt{3} + 3 i) x + 6 \sqrt{3} i = 0$

(iv) $6 x^{2} - 17 i x - 12 = 0$

x^{2} + 10 i x - 21 = 0

x^{2} + (1 - 2 i) x - 2 i = 0

x^{2} - (2 \sqrt{3} + 3 i) x + 6 \sqrt{3} i = 0

6 x^{2} - 17 i x - 12 = 0

x^{2} - (3 \sqrt{2} + 2 i) x + 6 \sqrt{2 i} = 0

x^{2} - (3 \sqrt{2} + 2 i) x + 6 \sqrt{2 i} = 0

x^{2} + 1 = 0

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