Question

Solve the following quadratic equation by factorization method:
$n^2+n-42=0$

Answer 1

The given quadratic equation is,
$n^2+n-42=0$
By factorization,
$n^2+7n-6n-42=0$
$\Rightarrow n(n+7)-6(n+7)=0$
$\Rightarrow (n+7)(n-6)=0$
$\Rightarrow (n-6)=0$ or $(n+7)=0$
$\Rightarrow n=6$ or $n=-7$