Solve the following quadratic equation by factorization method only $9 x^{2} + 4 = 0$

Open in App

Solution

We have,
$9 x^{2} + 4 = 0$

$\Rightarrow {(3 x)}^{2} - 4 (- 1) = 0$

$\Rightarrow {(3 x)}^{2} - 2 (i^{2}) = 0 [∵ i^{2} = - 1]$

$\Rightarrow {(3 x)}^{2} - {(2 i)}^{2} = 0$

$\Rightarrow (3 x - 2 i) (3 x + 2 i) = 0$

$[∵ a^{2} - b^{2} = (a - b) (a + b)]$

$\Rightarrow 3 x = 2 i o r 3 x = - 2 i$

$\Rightarrow x = \frac{2 i}{3} o r x = \frac{- 2 i}{3}$
Hence, ther roots are $\frac{2 i}{3} a n d \frac{- 2 i}{3}$

Suggest Corrections

Similar questions

Solve the following quadric equations by factorization method only $9 x^{2} + 4 = 0$

Solve the following quadratic equation by factorization.
$9 x^{2} - 3 x - 2 = 0$

9 x^{2} - 6 b^{2} x - (a^{4} - b^{4}) = 0

x^{2} + 1 = 0

9 x^{2} - 9 (a + b) x + (2 a^{2} + 5 a b + 2 b^{2}) = 0

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program