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Question

Solve the following quadratic equation by factorization, the roots are 0,1
3(7x+15x3)4(5x37x+1)=11;x35,17

A
True
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B
False
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Solution

The correct option is A True
3(7x+15x3)4(5x37x+1)=11

Let 7x+15x3=p

3p4p=11
3p24=11p
3p211p4=0
3p212p+p4=0
3p(p4)+1(p4)=0
(p4)(3p+1)=0
p4=0 and 3p+1=0
p=4 and p=13
7x+15x3=4 and 7x+15x3=13

7x+1=20x12 and 21x+3=5x+3
13x=13 and 26x=0
x=1 and x=0

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