Question

Solve the following quadratic equation by factorization, the roots are :
(2x + 3)(3x - 7) = 0

• A. $-\frac{2}{3},\frac{3}{7}$
• B. $-\frac{7}{2},\frac{7}{3}$
• C. $-\frac{3}{2},\frac{7}{3}$
• D. $-\frac{3}{7},\frac{3}{5}$

Answer 1

The correct option is C $-\frac{3}{2},\frac{7}{3}$

$\Rightarrow$ $(2x+3)(3x-7)=0$

$\Rightarrow$ $2x+3=0$ and $3x-7=0$

$\Rightarrow$ $2x=-3$ and $3x=7$

$\Rightarrow$ $x=-\frac{3}{2}$ and $x=\frac{7}{3}$

$\therefore$ The roots are $-\frac{3}{2},\frac{7}{3}.$