Question

Solve the following quadratic equation by factorization, the roots are :$+4,-4$
$\frac{16}{x}-1=\frac{15}{x+1};x\ne 0,-1$

• A. True
• B. False

Answer 1

The correct option is A True

$\frac{16}{x}-1=\frac{15}{x+1}$

$\Rightarrow$ $\frac{16-x}{x}=\frac{15}{x+1}$

$\Rightarrow$ $(16-x)(x+1)=15x$

$\Rightarrow$ $16x+16-x^2-x=15x$

$\Rightarrow$ $16-x^2=0$

$\Rightarrow$ $x^2=16$

$\Rightarrow$ $x=\pm 4$

$\therefore$ Roots given in question are correct.