Question

Solve the following quadratic equation by factorization, the roots are :
$48x^2$$-$ $13x-1=0$

• A. $-\frac{1}{16},\frac{1}{2}$
• B. $-\frac{1}{16},\frac{1}{4}$
• C. $-\frac{1}{6},\frac{1}{3}$
• D. $-\frac{1}{16},\frac{1}{3}$

Answer 1

Answer: (D)

$-\frac{1}{16},\frac{1}{3}$

$48x^2-13x-1=0$

$\Rightarrow$ $48x^2-16x+3x-1=0$

$\Rightarrow$ $16x(3x-1)+1(3x-1)=0$

$\Rightarrow$ $(16x+1)(3x-1)=0$

$\Rightarrow$ $16x+1=0$ and $3x-1=0$

$\Rightarrow$ $x=-\frac{1}{16}$ and $x=\frac{1}{3}$

$\Rightarrow$ $x=-\frac{1}{16},\frac{1}{3}$