Question

Solve the following quadratic equation by factorization, the roots are :
$5x^2-3x-2=0$

• A. $-\frac{2}{3},1$
• B. $-\frac{2}{5},1$
• C. $-\frac{2}{4},1$
• D. $-\frac{2}{5},3$

Answer 1

Answer: (B)

$-\frac{2}{5},1$

$5x^2-3x-2=0$

$\Rightarrow$ $5x^2-5x+2x-2=0$

$\Rightarrow$ $5x(x-1)+2(x-1)=0$

$\Rightarrow$ $(5x+2)(x-1)=0$

$\Rightarrow$ $5x+2=0$ and $x-1=0$

$\Rightarrow$ $x=-\frac{2}{5}$ and $x=1$

$\therefore$ $x=-\frac{2}{5},1$