Question

Solve the following quadratic equation by factorization, the roots are :$\frac{a}{2}$, $-a$
$2x^2+ax-a^2=0$

• A. True
• B. False

Answer 1

The correct option is A True

$2x^2+ax-a^2=0$

$\Rightarrow$ $2x^2+2ax-ax-a^2=0$

$\Rightarrow$ $2x(x+a)-a(x+a)=0$

$\Rightarrow$ $(x+a)(2x-a)=0$

$\Rightarrow$ $x+a=0$ and $2x-a=0$

$\therefore$ $x=-a$ and $x=\frac{a}{2}$

$\therefore$ The roots given in question are correct.