Question

Solve the following quadratic equation by using formula method:
$2x^2-3x=2$.

Answer 1

Roots of a quadratic equation $a{x}^2+bx+c=0$ are given by the formula,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Transforming the given equation in standard form, $2x^2-3x-2=0$, we get $a=2,b=-3$ and $c=-2$.

Substituting the values we get,

$x=\frac{-(-3)\pm \sqrt{(-3{)}^2-4\times 2\times (-2)}}{2\times 2}$

$x=\frac{3\pm \sqrt{25}}{4}=\frac{3\pm 5}{4}$

The roots of the equation are $x=2,-\frac{1}{2}$.