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Question

Solve the following quadratic equation:
4x3=52x+3,x0,32

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Solution

4x3=52x+3

(43x)x=52x+3

(43x)(2x+3)=5x

8x+126x29x=5x

6x2+6x12=0

x2+x2=0

x2+(21)x2=0

x2+2xx2=0

x(x+2)1(x+2)=0

(x+2)(x1)=0

when

x+2=0

x=2

and

x1=0

x=1

So x= 1 and -2


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