4x−3=52x+3
⇒(4−3x)x=52x+3
⇒(4−3x)(2x+3)=5x
⇒8x+12−6x2−9x=5x
⇒6x2+6x−12=0
⇒x2+x−2=0
⇒x2+(2−1)x−2=0
⇒x2+2x−x−2=0
⇒x(x+2)−1(x+2)=0
⇒(x+2)(x−1)=0 when
x+2=0
x=−2
and
x−1=0
x=1
So x= 1 and -2
Solve each of the following quadratic equations: 4x−3=52x+3,x≠0,−32