Question

Solve the following quadratic equation using formula.

$2x^2+5x-2=0$, then $x=$

Answer 1

Given equation is:

$2x^2+5x-2=0$
Applying quadratic formula,
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$
$a=2,b=5,c=-2$

$x=\frac{5\pm \sqrt{25-4\left(2\right)(-2)}}{2\times 2}$

$\therefore x=\frac{5\pm \sqrt{41}}{4}$