Question

Solve the following quadratic equation using formula method:
$6x^2-7x-1=0$

Answer 1

Given, $6x^2-7x-1=0$

Comparing with $a{x}^2+bx+c=0$, we get
$a=6,b=-7$ and $c=-1$

Now,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-(-7)\pm \sqrt{(-7{)}^2-4(6\left)\right(-1)}}{2\times 6}$

$=\frac{7\pm \sqrt{49+24}}{12}$

$=\frac{7\pm \sqrt{73}}{12}$

$\therefore$ Solution set $=\{\frac{7+\sqrt{73}}{12},\frac{7-\sqrt{73}}{12}\}$