Question

Solve the following quadratic equation using the Standard Quadratic Formula
3$x^2$ + 5x - 9 = 0

Answer 1

$3x^2+5x-9=0$
We know that the quadratic formula is $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$, therefore, substitute $a=3,b=5$ and $c=-9$ in $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ as follows:

$x=\frac{-5\pm \sqrt{5^2-4\left(3\right)(-9)}}{2\times 3}$

$=\frac{-5\pm \sqrt{25+108}}{6}$

$=\frac{-5\pm \sqrt{133}}{6}$