Question

Solve the following quadratic equation $x^2+4x-5=0$ by completing the square method.

Answer 1

Given quadratic equation is

$x^2+4x-5=0$

$⟹(x+2{)}^2-4-5=0$

$⟹(x+2{)}^2-9=0$

$⟹(x+2{)}^2-3^2=0$

$⟹(x+5)(x-1)=0$

$⟹x=1,-5$