Question

Solve the following quadratic equations by factorise:
Q.(ii). $2x^2+x-6=0$

Answer 1

$$\begin{gathered} 2{\mathrm{x}}^2+\mathrm{x}-6=0 \\ \Rightarrow 2{\mathrm{x}}^2+4\mathrm{x}-3\mathrm{x}-6=0 \\ \Rightarrow 2\mathrm{x}\left(\mathrm{x}+2\right)-3\left(\mathrm{x}+2\right)=0 \\ \Rightarrow \left(2\mathrm{x}-3\right)\left(\mathrm{x}+2\right)=0 \\ \Rightarrow 2\mathrm{x}-3=0\mathrm{or}\mathrm{x}+2=0 \\ \Rightarrow \mathrm{x}=\frac{3}{2}\mathrm{or}\mathrm{x}=-2 \end{gathered}$$