Solve the following quadratic equations by factorization:

$\frac{1}{x - 1} - \frac{1}{x + 5} = \frac{6}{7}, x \neq 1, - 5$

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Solution

We have been given

Therefore,

or,

Hence, x = 2 or x = −6.

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Similar questions

Q. Solve each of the following quadratic equations:

\frac{1}{x - 1} - \frac{1}{x + 5} = \frac{6}{7}, x \neq 1, - 5

[CBSE 2010]

Q. Solve each of the following quadratic equations:

(i)

\frac{1}{x - 1} - \frac{1}{x + 5} = \frac{6}{7}, x \neq 1, - 5

(ii)

\frac{1}{2 x - 3} + \frac{1}{x - 5} = 1 \frac{1}{9}, x \neq \frac{3}{2}, 5

[CBSE 2017]

Q. Solve the following quadratic equations by factorization:

\frac{1}{x} - \frac{1}{x - 2} = 3, x \neq 0, 2

Q. Solve the following quadratic equations by factorization:

\frac{1}{(x - 1) (x - 2)} + \frac{1}{(x - 2) (x - 3)} + \frac{1}{(x - 3) (x - 4)} = \frac{1}{6}

Solve the following quadratic equation by factorization.
$\frac{1}{(x - 1) (x - 2)} + \frac{1}{(x - 2) (x - 3)} + \frac{1}{(x - 3) (x - 4)} = \frac{1}{6}$

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Solve the following quadratic equations by factorization: 1x-1-1x+5=67, x≠1, -5

We have been given Therefore, or, Hence, x = 2 or x = −6.

Solve the following quadratic equations by factorization:

$\frac{1}{x - 1} - \frac{1}{x + 5} = \frac{6}{7}, x \neq 1, - 5$

We have been given

Therefore,

or,

Hence, x = 2 or x = −6.