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Question

Solve the following quadratic equations by factorization method :
4x24a2x+a4b4=0

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Solution

4x24a2x+a4b4=0
4x22[2(a2+b2)+2(a2b2)]x+(a2b2)(a2+b2)=0
4x22(a2+b2)x2(a2b2)x+(a2b2)(a2+b2)=0
2x[2x(a2+b2)]=(ab2)[2x(a2+b2)]=0
[2x(a2b2)][2x(a2+b2)]=0
2x=a2b2
x=a2b22
or, 2x=a2+b2
x=a2+b22

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