Question

Solve the following quadratic equations by factorization method.
4y² + 4y +1 = 0

Answer 1

Given: 4y² + 4y +1 = 0
On splitting the middle term 4y as 2y + 2y, we get:
4y² + 2y + 2y + 1 = 0
=> 2y(2y + 1) + 1(2y + 1) = 0
=> (2y + 1) (2y + 1) = 0
=> (2y + 1)² = 0
=> 2y + 1 = 0 or y =$\frac{-1}{2}$ , $\frac{-1}{2}$
Therefore, the solution of the given equation is y = $\frac{-1}{2}$,$\frac{-1}{2}$.