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Question

Solve the following quadratic equations by factorization method :
9x29(a+b)x+(2a2+5ab+2b2)=0

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Solution

9x29(a+b)x+(2a2+5ab+2b2)=0
9x29(a+b)x+[2a(a+2b)+b(a+2b)]=0
9x29(a+b)x+[(2a+b)(a+2b)]=0
9x23[(a+2b)(2a+b)]x+[(2a+b)(a+2b)]=0
3x[3x(a+2b)][3x(2a+b)]=0
3x=a+2b
x=a+2b3
or,
3x=2a+b
x=2a+b3

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