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Byju's Answer
Standard IX
Mathematics
Zeroes of a Polynomial
Solve the fol...
Question
Solve the following quadratic equations by factorization method:
x
x
+
1
+
x
+
1
x
=
34
15
A
{
−
5
2
,
3
2
}
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B
{
5
2
,
3
2
}
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C
{
−
5
2
,
−
3
2
}
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D
None of these
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Solution
The correct option is
A
{
−
5
2
,
3
2
}
x
x
+
1
+
x
+
1
x
=
34
15
⇒
15
x
2
+
15
(
x
+
1
)
2
=
34
x
(
x
+
1
)
[ multiplying both sides by
15
x
(
x
+
1
)
]
⇒
15
x
2
+
15
(
x
2
+
2
x
+
1
)
=
34
x
2
+
34
x
⇒
15
x
2
+
15
x
2
+
30
x
+
15
=
34
x
2
+
34
x
⇒
4
x
2
+
4
x
−
15
=
0
⇒
4
x
2
+
10
x
−
6
x
−
15
=
0
⇒
2
x
(
2
x
+
5
)
−
3
(
2
x
+
5
)
=
0
⇒
(
2
x
+
5
)
(
2
x
−
3
)
=
0
⇒
2
x
+
5
=
0
and
2
x
−
3
=
0
∴
x
=
−
5
2
and
x
=
3
2
Suggest Corrections
0
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