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Byju's Answer
Standard X
Mathematics
Quadratic Equations
Solve the fol...
Question
Solve the following quadratic equations by factorization:
x
+
1
x
-
1
+
x
-
2
x
+
2
=
4
-
2
x
+
3
x
-
2
;
x
≠
1
,
-
2
,
2
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Solution
x
+
1
x
-
1
+
x
-
2
x
+
2
=
4
-
2
x
+
3
x
-
2
⇒
(
x
+
1
)
(
x
+
2
)
+
(
x
-
1
)
(
x
-
2
)
(
x
-
1
)
(
x
+
2
)
=
4
(
x
-
2
)
-
(
2
x
+
3
)
x
-
2
⇒
(
x
2
+
2
x
+
x
+
2
)
+
(
x
2
-
2
x
-
x
+
2
)
x
2
+
2
x
-
x
-
2
=
4
x
-
8
-
2
x
-
3
x
-
2
⇒
x
2
+
3
x
+
2
+
x
2
-
3
x
+
2
x
2
+
x
-
2
=
2
x
-
11
x
-
2
⇒
2
x
2
+
4
x
2
+
x
-
2
=
2
x
-
11
x
-
2
⇒
(
2
x
2
+
4
)
(
x
-
2
)
=
(
2
x
-
11
)
(
x
2
+
x
-
2
)
⇒
2
x
3
-
4
x
2
+
4
x
-
8
=
2
x
3
+
2
x
2
-
4
x
-
11
x
2
-
11
x
+
22
⇒
2
x
3
-
4
x
2
+
4
x
-
8
=
2
x
3
-
9
x
2
-
15
x
+
22
⇒
2
x
3
-
2
x
3
-
4
x
2
+
9
x
2
+
4
x
+
15
x
-
8
-
22
=
0
⇒
5
x
2
+
19
x
-
30
=
0
⇒
5
x
2
+
25
x
-
6
x
-
30
=
0
⇒
5
x
(
x
+
5
)
-
6
(
x
+
5
)
=
0
⇒
(
5
x
-
6
)
(
x
+
5
)
=
0
⇒
5
x
-
6
=
0
,
x
+
5
=
0
⇒
x
=
6
5
,
x
=
-
5
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Similar questions
Q.
Solve the following quadratic equations by factorization:
x
+
1
x
-
1
-
x
-
1
x
+
1
=
5
6
,
x
≠
1
,
-
1