Solve the following quadratic equations by factorization:

$x - \frac{1}{x} = 3, x \neq 0$

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Solution

We have been given

Therefore,

or,

Hence, or .

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Similar questions

\frac{x + 1}{x - 1} - \frac{x - 1}{x + 1} = \frac{5}{6}, x \neq 1, - 1

\frac{x - 1}{x - 2} + \frac{x - 3}{x - 4} = 3 \frac{1}{3}, x \neq 2, 4

x^{2} - (\sqrt{3} + 1) x + \sqrt{3} = 0

\frac{x + 1}{x - 1} + \frac{x - 2}{x + 2} = 4 - \frac{2 x + 3}{x - 2}; x \neq 1, - 2, 2

{(x - \frac{1}{2})}^{2} = 4

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