Question

Solve the following quadratics $13x^2+7x+1=0$

Answer 1

$13x^2+7x+1=0\text{We will discriminant rule,}x=\frac{-b\pm \sqrt{D}}{2a}...\left(A\right)whereD=b^2-4ac=(7{)}^2-\mathrm{4.13.1}=49-52=-3Thus,from(A)x=\frac{-7\pm \sqrt{-3}}{2.13}=\frac{(-7)\pm \sqrt{3i}}{26}Thus\therefore x=\frac{-7}{26}\pm \frac{\sqrt{3}}{26}i$