Solve the following quadratics $17 x^{2} + 28 x + 12 = 0$

Open in App

Solution

$17 x^{2} + 28 x + 12 = 0 We will discriminant rule, x = \frac{- b \pm \sqrt{D}}{2 a} . . . (A) w h e r e D = b^{2} - 4 a c = (28)^{2} - 4.17.12 = 784 - 816 = - 32 f r o m (A) x = \frac{- 28 \pm \sqrt{- 32}}{2.17} = \frac{- 28 \pm \sqrt{4 \sqrt{2 i}}}{34} ∴ x = \frac{- 14 \pm 2 \sqrt{2 i}}{17}$

Suggest Corrections

Similar questions

x^{5} - 6 x^{4} - 17 x^{3} + 17 x^{2} + 6 x - 1 = 0

x^{2} - 7 x + 12 = 0

28 x^{3} - 9 x^{2} + 1 = 0

Solve each of the following quadratic equations:
$6 x^{2} + x - 12 = 0$

Solve $21 x^{2} - 28 x + 10 = 0$

Join BYJU'S Learning Program