Question

Solve the following quadratics $5x^2-6x+2=0$

Answer 1

$5x^2-6x+2=0\text{We will discriminant rule},x=\frac{-b\pm \sqrt{D}}{2a}....\left(A\right)whereD=b^2-4ac=(-6{)}^2-\mathrm{4.5.2}=36-40=-4from(A)x=\frac{-(-6)\pm \sqrt{-4}}{2.5}=\frac{6\pm 2i}{10}=\frac{3\pm i}{5}\therefore x=\frac{3}{5}+\frac{i}{5},\frac{3}{5}-\frac{i}{5}$