Solve the following quadratics $8 x^{2} - 9 x + 3 = 0$

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Solution

$8 x^{2} - 9 x + 3 = 0 We will discriminant rule, x = \frac{- b \pm \sqrt{D}}{2 a} . . . (A) w h e r e D = b^{2} - 4 a c = (- 9)^{2} - 4.8.3 = 81 - 96 = - 15 x = \frac{- b \pm \sqrt{D}}{2 a} = \frac{- (- 9) \pm \sqrt{15}}{2.8} = \frac{9 \pm \sqrt{15 i}}{16} T h u s, ∴ x = \frac{9 \pm \sqrt{15 i}}{16}$

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