Solve the following quadric equations by factorization method only $x^{2} + 2 x + 5 = 0$

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Solution

$x^{2} + 2 x + 5 = 0 Now, completing the squares, we get (x + 1)^{2} + 4 = 0 \Rightarrow (x + 1)^{2} - 2 i^{2} = 0 \Rightarrow (x + 1 + 2 i) (x + 1 - 2 i) = 0 \Rightarrow (x + 1 + 2 i) = 0 O r (x + 1 - 2 i) = 0 ∴ x = - 1 - 2 i, - 1 + 2 i$

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