Question

Solve the following question:

$\frac{\left(Z\right)+(Z+7)+(Z+3)}{4}=25$

• A. 30
• B. 31
• C. 2
• D. 4

Answer 1

The correct option is A

30

$\frac{\left(Z\right)+(Z+7)+(Z+3)}{4}=25$

Multiplying by 4 on both sides.

$\Rightarrow \frac{\left(Z\right)+(Z+7)+(Z+3)}{4}\times 4=25\times 4$

$\Rightarrow \left(Z\right)+(Z+7)+(Z+3)=100$

$Z+Z+Z+7+3=100$

Subtracting 10 from both sides

$3Z+10-10=100-10$

$3Z=90$

dividing by 3 on both sides

$\frac{3Z}{3}=\frac{90}{3}$

$Z=30$

Check:

$\frac{\left(Z\right)+(Z+7)+(Z+3)}{4}=25$

LHS: $\frac{\left(30\right)+(30+7)+(30+3)}{4}$

$=\frac{100}{4}=25=RHS$