Question 127

Solve the following question:

Rahul walks 12 m North from his house and turns West to walk 35 m to reach his friend's house. While returning, he walks diagonally from his friend's house to reach back to his house. What distance did he walk while returning?

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Solution

Let Rahul walked $x$ m while returning home.

In $Δ A B C$ , by using Pythagoras theorem, we get
$A C^{2} = A B^{2} + B C^{2} \Rightarrow A C^{2} = (12)^{2} + (35)^{2} \Rightarrow A C^{2} = 144 + 1225 = 1369 \Rightarrow A C = \sqrt{1369} \Rightarrow A C = 37 m$
Hence, Rahul walked 37m distance for returning to his house diagonally.

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Question 127 Solve the following question: Rahul walks 12 m North from his house and turns West to walk 35 m to reach his friend's house. While returning, he walks diagonally from his friend's house to reach back to his house. What distance did he walk while returning?

Let Rahul walked x m while returning home. In ΔABC, by using Pythagoras theorem, we get AC2=AB2+BC2⇒AC2=(12)2+(35)2⇒AC2=144+1225=1369⇒AC=√1369⇒AC=37 m Hence, Rahul walked 37m distance for returning to his house diagonally.

Question 127

Solve the following question:

Rahul walks 12 m North from his house and turns West to walk 35 m to reach his friend's house. While returning, he walks diagonally from his friend's house to reach back to his house. What distance did he walk while returning?