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Standard VII

Mathematics

Applications (Word Problem)

Solve the fol...

Question

Solve the following riddle:
I am a number. Tell my identity!
Take me seven times over and add a fifty! To
reach a triple century, you still need forty.

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Solution

Let the number be $n$ .
According to the question, $7 n + 50 + 40 = 300$
$\Rightarrow 7 n + 90 = 300 \Rightarrow 7 n = 300 - 90$
$\Rightarrow 7 n = 210$
$\Rightarrow n = \frac{210}{7}$
$∴ n = 30$
Thus, the required number is $30$ .

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Similar questions

Q. Solve the following riddle:
I am a number. Tell my identity!
Take me seven times over and add a fifty! To
Reach a triple century, you still need forty.

Solve the following riddle:

I am a number,

Tell my identity!

Take me seven times over

And add a fifty!

To reach a triple century

You still need forty!

Q. Solve the following riddle:
I am a number
Tell my identity.
Take me two times over
And add a thirty six.
To reach a century
You still need four.

Solve the following riddles, you may yourself construct such riddles.

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(i) Go round a square

Counting every corner

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To get exactly thirty four!

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Make an upcount from me

If you make no mistake

You will get twenty three!

(iii) I am a special number

Take away from me a six!

A whole cricket team

You will still be able to fix!

(iv) Tell me who I am

I shall give a pretty clue!

You will get me back

If you take me out of twenty two!

Q. Solve the following riddle by finding the unknown number :

" A t h i r d o f m e t i m e s h a l f o f m e i s a s i x t h m o r e t h a n f o u r . F i n d m y d i v i s i o n a n d m u l t i p l i c a t i o n e q u a t i o n s t o k n o w a b o u t m e m o r e "

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Applications (Word Problem)

Standard VII Mathematics

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Solve the following riddle: I am a number. Tell my identity! Take me seven times over and add a fifty! To reach a triple century, you still need forty.

Let the number be n. According to the question, 7n+50+40=300 ⇒7n+90=300⇒7n=300−90 ⇒7n=210⇒n=2107∴n=30 Thus, the required number is 30.

Solve the following riddle:
I am a number. Tell my identity!
Take me seven times over and add a fifty! To
reach a triple century, you still need forty.

Let the number be $n$ .
According to the question, $7 n + 50 + 40 = 300$
$\Rightarrow 7 n + 90 = 300 \Rightarrow 7 n = 300 - 90$
$\Rightarrow 7 n = 210$
$\Rightarrow n = \frac{210}{7}$
$∴ n = 30$
Thus, the required number is $30$ .