Question

Solve the following simultaneous equation.

$12x+17y=53;17x+12y=63$

• A. $x=3,y=1$
• B. $x=2,y=1$
• C. $x=1,y=1$
• D. $x=9,y=1$

Answer 1

The correct option is A $x=3,y=1$

$12x+17y=53$ ...(i)
$17x+12y=63$ ...(ii)
On adding (i) and (ii) , we get
$29x+29y=116$
$\Rightarrow x+y=4$ ....(iii)
On subtracting (i) from (ii) , we get
$5x-5y=10$
$\Rightarrow x-y=2$ ....(iv)
On adding (iii) and (iv) , we get
$2x=6$
$\Rightarrow x=3$
By putting $x=3$ in (iii), we get
$3+y=4$
$\Rightarrow y=1$