Question

Solve the following simultaneous equations
$3a+5b=20;a+5b=22$

Answer 1

$3a+5b=20$

$a+5b=22$

subtracting both the equations, we get

$3a-a=20-22$

$2a=-2$

$a=-1$

$a+5b=22$

$5b=22-a=22+1=23$

$b=\frac{23}{5}$

Hence $a=-1$ and $b=\frac{23}{5}$