Solve the following simultaneous equations:
$4 m + 3 n = 18; 3 m - 2 n = 5$

m = 3, n = 2

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m = - 3, n = - 2

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m = 3, n = - 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m = - 3, n = 2

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Solution

The correct option is A $m = 3, n = 2$
Let $4 m + 3 n = 18$ --- (1)
and $3 m - 2 n = 5$ --- (2)
Multiplying the first equation by $2$ , we get $8 m + 6 n = 36$ -- (3)
Multiplying the second equation by $3$ , we get $9 m - 6 n = 15$ -- (4)
Adding equations 3, and 4 , we get
$17 m = 51$
$=> m = 3$
Now, putting $m = 3$ in equation 1 we get, $12 + 3 n = 18$
$=> 3 n = 6$
$=> n = 2$

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