wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following simultaneous equations graphically.
(1) 2x + 3y = 12 ; x – y = 1
(2) x – 3y = 1 ; 3x – 2y + 4 = 0
(3) 5x – 6y + 30 = 0 ; 5x + 4y – 20 = 0
(4) 3x – y – 2 = 0 ; 2x + y = 8
(5) 3x + y = 10 ; x – y = 2

Open in App
Solution

(1) 2x + 3y = 12
x 0 6 3
y 4 0 2
x – y = 1
x 0 1 3
y −1 0 2



The solution of the given equations is the point of intersection of the two line i.e(3, 2).

(2) x – 3y = 1
x 1 4 7
y 0 1 2

3x – 2y + 4 = 0
x 0 2 4
y 2 5 8



The solution of the given equations is the point of intersection of the two line i.e (-2,-1).

(3) 5x – 6y + 30 = 0
x 0 –6
y 5 0

5x + 4y – 20 = 0
x 0 4
y 5 0



The solution of the given equations is the point of intersection of the two line i.e (0, 5).

(4) 3x – y – 2 = 0
x 0 1
y –2 1

2x + y = 8
x 0 4
y 8 0


The solution of the given equations is the point of intersection of the two line i.e (2, 4).

(5) 3x + y = 10
x 0 1
y 10 7

x – y = 2
x 0 2
y –2 0


The solution of the given equations is the point of intersection of the two line i.e (3, 1).


flag
Suggest Corrections
thumbs-up
8
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equation of Line perpendicular to a given Line
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon