Solve the following simultaneous linear inequations graphically. x+2y≤10, x+y≤6, x≤4, x≥0 and y≥0
We draw the graph of the lines x+2y=10, x+y=6 and x=4
Table for line x+2y=10 or y=10−x2 is
x010y50
On putting (0, 0) in the inequality x+2y≤10, we get 0+0≤10 (true). So, the inequality lies towards the origin.
table for line x+y=6 or y=6−x is [1]
x06y60
On putting (0, 0) in the inequality x+y≤6, we get 0+0≤6 (true). So, the inequality lies towards the origin.
Line x=4 is the perpendicular line on the x-axis at a distance of 4 units from origin. [1]
Also, x≥0, y≥0, so every point of the shaded region lie in the first quadrant.
Now, plot all the points of the inequalities on a graph paper which are shown below [1]
[1]