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Question

Solve the following simultaneous linear inequations graphically. x+2y10, x+y6, x4, x0 and y0

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Solution

We draw the graph of the lines x+2y=10, x+y=6 and x=4

Table for line x+2y=10 or y=10x2 is

x010y50

On putting (0, 0) in the inequality x+2y10, we get 0+010 (true). So, the inequality lies towards the origin.

table for line x+y=6 or y=6x is [1]

x06y60

On putting (0, 0) in the inequality x+y6, we get 0+06 (true). So, the inequality lies towards the origin.

Line x=4 is the perpendicular line on the x-axis at a distance of 4 units from origin. [1]

Also, x0, y0, so every point of the shaded region lie in the first quadrant.

Now, plot all the points of the inequalities on a graph paper which are shown below [1]

[1]


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