Question

Solve the following simultaneously equation using elimination method
$4m+6n=54;3m+2n=28$

Answer 1

$Mulitply$ second equation by $3$ and $subract$ first equation from it,

$3(3m+2n)-(4m+6n)=3\left(28\right)-54$

$9m+6n-4m-6n=30$

$5m=30$

$m=6$

Substitute in first equation,

$4\left(6\right)+6n=54$

$6n=54-24$

$6n=30$

$n=5$

Thus $m=6$ and $n=5$

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