Question

Solve the following system by elimination method:
$5x-4y=-14$,$3x+2y=-4$

Answer 1

Given equations are

$5x-4y=-14$ ....(1)

and $3x+2y=-4$ ....(2)

Multiply equation (2) by $2$, we get

$6x+4y=-8$ ....(3)

Add equations (1) and (3) to eliminate $y$,

$11x=-22$

$\Rightarrow x=-2$

Substitute this value of $x$ in equation (1),

$5(-2)-4y=-14$

$\Rightarrow -10-4y=-14$

$\Rightarrow -4y=-4$

$\Rightarrow y=1$

Therefore, the solution is $x=-2,y=1$.